The Romanian national team was placed in Group A, alongside Denmark, Spain, and Montenegro, at the final tournament of the Under-19 European Football Championship, which will take place in Romania, between June 13\u201326.\u00a0<\/p>\n
Teams from Germany, Norway, England, and the Netherlands will compete in Group B of the Championship, which will be hosted on stadiums in Bucharest (Giule\u0219ti and Arcul de Triumf), Voluntari (Anghel Iord\u0103nescu), and Ploie\u0219ti (Ilie Oan\u0103).<\/p>\n
The top two teams from each group will qualify for the final tournament.\u00a0<\/p>\n
Romania was initially supposed to host the final tournament in 2021, but the competition was canceled due to the Covid-19 pandemic. The country has previously hosted the final tournament once, in 2011, when it finished last in Group A, with one draw (0-0 with Ireland) and two losses (1-3 to the Czech Republic, and 0-1 to Greece). The title was won then by Spain.\u00a0<\/p>\n
Romania\u2019s group is challenging. Spain, which is also the current U19 European champion and nine-time winner of the tournament in its current format, qualified by winning a difficult group with France, Italy, and Latvia, according to the FRF website<\/a>.<\/p>\n Denmark won its group with maximum points against Austria, Hungary, and Iceland.\u00a0<\/p>\n Montenegro will debut at a continental Under-19 final tournament after an exceptional run in another very balanced group from the elite round, hosted by Georgia. The team drew with Slovakia (1-1), defeated Poland 1-0, and beat Georgia 3-1.\u00a0<\/p>\n Romania\u2019s team, coached by Ion Marin, qualified directly for the final tournament. Romania had not participated in an Under-19 final tournament since 2022, when it lost all three matches.<\/p>\n